v^2+4v+9=2v

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Solution for v^2+4v+9=2v equation: 



v^2+4v+9=2v

We move all terms to the left:

v^2+4v+9-(2v)=0

We add all the numbers together, and all the variables

v^2+2v+9=0

a = 1; b = 2; c = +9;
Δ = b2-4ac
Δ = 22-4·1·9
Δ = -32
Delta is less than zero, so there is no solution for the equation

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